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Each side of a regular polygon is 5.2 m, and the perimeter is 36.9 m. Find the number of sides of the polygon.

A. What is asked?
- The number of sides of the polygon.

B. What are the given facts?
- Each side of the polygon measures 5.2 m.
- The perimeter of the polygon is 36.9 m.

C. What is the solution?
- Calculate the number of sides by dividing the perimeter by the length of one side.

D. What is the answer?
- The number of sides of the polygon.

Answer :

Sure, let's work through the problem step by step.

What is being asked?

We need to find the number of sides of a regular polygon (sometimes referred to as a polyhedron if the description is unique).

What are the given facts?

1. Each side of the polygon is 5.2 meters long.
2. The total perimeter of the polygon is 36.9 meters.

What is the solution approach?

To find the number of sides of the polygon, you can use the formula for the perimeter of a regular polygon:

[tex]\[ \text{Perimeter} = \text{Number of sides} \times \text{Side length} \][/tex]

Given that we know the perimeter (36.9 meters) and the side length (5.2 meters), we can rearrange the formula to solve for the number of sides:

[tex]\[ \text{Number of sides} = \frac{\text{Perimeter}}{\text{Side length}} \][/tex]

Solution:

1. Start with the provided perimeter, which is 36.9 meters.
2. Divide this perimeter by the side length, which is 5.2 meters.

[tex]\[
\text{Number of sides} = \frac{36.9}{5.2} \approx 7.096
\][/tex]

When you calculate it, you find that the number of sides is approximately 7.096. Since the number of sides must be a whole number, there might be further constraints or approximations in real-world scenarios leading to rounding considerations, but given the answer, a consideration around this conveys a fractional situation hence might result in needed context in technical scenarios or estimates.

The polygon, while abstractly can indicate a requirement for exact integer, directs any closest assumptions on fractional manner or rounding off contextually in practical situations.

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