High School

2. The mass of solid precipitates after performing a chemical reaction in Experiment 1 is 38.3 grams. The mass of the solids in Experiment 2 is 35.9 grams. What is the percent change of the mass from Experiment 1 to Experiment 2?

a. 6.3% increase
b. 6.3% decrease
c. 6.7% increase
d. 6.7% decrease

Answer :

Option b. To determine the percent change in mass from Experiment 1 to Experiment 2, we use the percent change formula. The calculation shows a 6.27% decrease in mass. Therefore, the answer is b. 6.3% decrease.

To find the percent change in mass from Experiment 1 to Experiment 2, we'll use the percent change formula:

[tex]\[ \text{Percent Change} = \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \times 100\% \][/tex]

Given:

Mass in Experiment 1 (Old Value): [tex]\( 38.3 \) grams[/tex]

Mass in Experiment 2 (New Value): [tex]\( 35.9 \) grams[/tex]

Using the formula:

[tex]\[ \text{Percent Change} = \frac{35.9 - 38.3}{38.3} \times 100\% \][/tex]

[tex]\[ \text{Percent Change} = \frac{-2.4}{38.3} \times 100\% \][/tex]

[tex]\[ \text{Percent Change} \approx -0.0627 \times 100\% \][/tex]

[tex]\[ \text{Percent Change} \approx -6.27\% \][/tex]

Rounding to the nearest tenth, we have [tex]\( -6.3\% \).[/tex]

Therefore, the percent change of the mass from Experiment 1 to Experiment 2 is approximately a [tex]\( 6.3\% \)[/tex] decrease. So, the correct answer is: b.[tex]\( 6.3\% \) decrease[/tex]

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