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1. How many grams of sulfur dioxide could be formed when 299 grams of [tex]$H_2SO_4$[/tex] reacts?

[tex] \_\_ \text{Cu} + \_\_ \text{H}_2\text{SO}_4 \rightarrow \_\_ \text{CuSO}_4 + \_\_ \text{SO}_2 + \_\_ \text{H}_2\text{O} [/tex]

A. 97.6 g
B. 195 g
C. 391 g
D. 48.8 g

Answer :

Answer:

cu+97.6g+48.8g

prabin Shrestha

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Final answer:

To find the grams of sulfur dioxide formed from the reaction, calculate the molar mass of H2SO4, use stoichiometry to find moles of SO2, then convert moles to grams resulting in 97.6 g.

Explanation:

The balanced chemical equation provided is:
___Cu + ___H2SO4 → ___CuSO4 + ___SO2 + ___H2O

To determine the grams of sulfur dioxide formed:
1. Calculate the molar mass of H2SO4. 2. Use stoichiometry to find the moles of sulfur dioxide produced. 3. Finally, convert moles back to grams.

Therefore, the correct answer is (a) 97.6 g, as 299 grams of H2SO4 will produce 97.6 grams of SO2.

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