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Using technology, determine the line of fit, where [tex]x[/tex] represents the average daily temperature and [tex]y[/tex] represents the total ice cream sales. Round values to the nearest tenth.

A. [tex]y = 3.8x - 109.2[/tex]

B. [tex]y = -3.8x - 100.2[/tex]

C. [tex]\hat{y} = 6.5x - 279.1[/tex]

Answer :

Sure! Let's find the line of best fit for the given data, where [tex]\( x \)[/tex] represents the average daily temperature in degrees Fahrenheit, and [tex]\( y \)[/tex] represents the total ice cream sales in dollars.

The data points are:

- Temperature (°F): 58.2, 64.2, 64.3, 66.8, 68.4, 71.6, 72.7, 76.2, 77.8, 82.8
- Ice Cream Sales ([tex]$): 112, 135, 138, 146, 166, 180, 188, 199, 220, 280

### Steps to Determine the Line of Best Fit:

1. Identify the Variables:
- Let \( x \) be the temperature.
- Let \( y \) be the ice cream sales.

2. Use Linear Regression:
- We aim to find the equation of the line form \( y = mx + b \), where:
- \( m \) is the slope.
- \( b \) is the y-intercept.

3. Calculate the Slope (\( m \)) and Y-intercept (\( b \)):
- Using statistical tools or technology, we analyze the data points to calculate these values, ensuring they fit the data closely.

4. Round the Values:
- Round the slope and y-intercept to the nearest tenth for approximation.

### Result:

After performing the calculation, the line of best fit is given by:

\[ \hat{y} = 6.5x - 279.1 \]

- Slope (\( m \)) = 6.5: This means that for every increase of 1 degree Fahrenheit in temperature, ice cream sales are expected to increase by $[/tex]6.50.
- Y-intercept ([tex]\( b \)[/tex]) = -279.1: This value represents the expected ice cream sales when the temperature is 0°F, though it might not be directly interpretable within the context of our data.

This line provides the best prediction of ice cream sales based on the temperature data provided.

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