Answer :
Final answer:
The percent yield of carbon disulfide is 29.7%.
Explanation:
The percent yield can be calculated using the formula:
Percent yield = (Actual yield / Theoretical yield) x 100
To find the percent yield of carbon disulfide, we need to determine the theoretical yield. The balanced chemical equation for the reaction is:
2 SO2 + C → 2 CS2 + 2 O
From the equation, we can see that 2 moles of sulfur dioxide (SO2) react with 1 mole of carbon (C) to produce 2 moles of carbon disulfide (CS2). We can use the molar mass of sulfur dioxide (64.07 g/mol) to calculate the moles of sulfur dioxide:
35.9 g SO2 x (1 mol SO2 / 64.07 g SO2) = 0.5608 mol SO2
Using the stoichiometric ratio from the balanced equation, we can determine the moles of carbon disulfide:
0.5608 mol SO2 x (2 mol CS2 / 2 mol SO2) = 0.5608 mol CS2
Finally, we can convert the moles of carbon disulfide to grams:
0.5608 mol CS2 x (76.14 g CS2 / 1 mol CS2) = 42.74 g CS2
Now, we can calculate the percent yield:
Percent yield = (12.7 g / 42.74 g) x 100 = 29.7%
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