Answer :
Final answer:
Two bulbs rated 100 W and 220 V and 60 W and 220 V are connected in parallel to an electric field of 220V. The current drawn by the bulbs from the mains is 666.67 Amps.
Explanation:
In a parallel circuit, the voltage across each component is the same. So, both bulbs will operate at 220V. To find the current drawn by the bulbs, we can use Ohm's Law: current (I) = voltage (V) / resistance (R). Power (P) can be calculated using the formula: power (P) = voltage (V) * current (I).
Let's calculate the current drawn by each bulb: Bulb 1: Power (P) = 100 W, Voltage (V) = 220 V, Resistance (R) = (V^2) / P, Resistance (R) = (220^2) / 100 = 484 Ω. Bulb 2: Power (P) = 60 W, Voltage (V) = 220 V, Resistance (R) = (V^2) / P, Resistance (R) = (220^2) / 60 = 806.7 Ω.
The total current drawn by the bulbs can be calculated by calculating the total resistance in the circuit and using Ohm's Law again: Total resistance (R) = (1 / R1) + (1 / R2), Total resistance (R) = (1 / 484) + (1 / 806.7) = 0.0021 + 0.0012 = 0.0033 Ω, Total current (I) = voltage (V) / total resistance (R) = 220 / 0.0033 = 666.67 Amps