Answer :
The hot resistance of a light bulb rated 60 W, 120 V is 240 ohms. This is calculated using the formula R = V²/P, where R is the resistance, V is the voltage, and P is the power.
The hot resistance of a light bulb can be calculated using the formula:
R = V²/P
where R is the resistance, V is the voltage, and P is the power.
In this case, the power rating is 60 W and the voltage is 120 V. Plugging in these values, we get:
R = (120 V)² / 60 W
R = 14400 V²/W / 60 W
R = 240 ohms
Therefore, the hot resistance of the light bulb rated 60 W, 120 V is 240 ohms.
So the answer is (d) 240 ohms.
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