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A machine gun, with a mass of 39.4 kg, fires 11.4-gram bullets at a velocity of 764 m/s. The gun fires at a rate of 399 rounds per minute. What is the average force exerted on the gun mount?

Answer :

The average force exerted on the gun is determined as 167.2 N.

What is the average force exerted on the gun?

The average force exerted on the gun is calculated by applying Newton's second law of motion, which states that change in momentum of an object is directly proportional to the average force applied.

ΔP = P₂ - P₁

where;

  • P₁ is the momentum of the bullet
  • P₂ is the momentum of the gun

The change in momentum of the system;

ΔP = (39.4 x 764 ) - ( 0.0114 x 399 x 1 min/60s)

ΔP = 30,101.5 kg.m/s

The average force exerted on the gun is calculated as follows;

F = ΔP /t

F = 30,101.5 kg.m/s ( 3 min x 60 s)

F = 167.2 N

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The missing part of the question is below:

What is the average force exerted on the gun mount for 3 mins?

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