Answer :
Final answer:
The change in entropy (ΔS) for the vaporization of ethanol, calculated using the formula ΔS = ΔH/T, is approximately 111.8 J/mol*K.
Explanation:
The change in entropy (ΔS) for the vaporization of ethanol can be calculated using the formula ΔS = ΔH/T, where ΔH is the molar heat of vaporization and T is the absolute temperature (in Kelvin). The given molar heat of vaporization of ethanol is 39.3 kJ/mol, and this should be converted to J/mol for the calculations, which becomes 39300 J/mol. The boiling point of ethanol is given as 78.3 degrees Celsius. If we want to convert this to Kelvin, we add 273.15, giving us 351.45 K. Now, substituting into the formula gives ΔS = 39300 J/mol / 351.45 K = 111.8 J/mol*K. So the change in entropy for the vaporization of ethanol is 111.8 J/mol*K.
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