Answer :
To determine the shearing stress at joint C with a pin diameter of 46 mm and a force of 24 kN applied at joint B, calculate the cross-sectional area A and then use the formula \tau = F/A. The result is approximately 14.44 MPa.
To determine the shearing stress acting at joint C with a pin diameter of 46 mm when a vertical force of F=24 kN is applied at joint B, we first need to calculate the cross-sectional area (A) where the shear will occur. This is found using the formula for the area of a circle, A = \/pi * (d/2)^2, where d is the diameter of the pin. Once we have the area, we can calculate the shear stress (\tau) using the formula \tau = F/A, where F is the force applied.
First, calculate the area:
A = \/pi * (0.046/2)^2
A = 0.00166129032 m^2
Now, calculate the shear stress:
\tau = F/A
\tau = 24000 N / 0.00166129032 m^2
\tau = 14437695.8895 Pascals or 14.44 MPa (approx.)
Therefore, the shearing stress at joint C is approximately 14.44 MPa.