High School

What is the entropy change when 1.55 moles of [tex]\text{CCl}_2\text{F}_2[/tex] vaporize at 25°C? (Given entropy = 17.2 kJ/(mol*K) at 25°C)

a. 26.7 kJ/mol
b. 17.2 kJ/mol
c. 38.2 kJ/mol
d. 7.1 kJ/mol

Answer :

Final answer:

The calculation of entropy change during vaporization of CCl2F2 at 25°C requires the enthalpy of vaporization, which is not provided; hence, the question cannot be answered with the provided data.

Explanation:

The question is asking for the entropy of CCl2F2 when it vaporizes at 25°C with a given entropy of 17.2 kJ/(mol*K) at 25°C.

However, the information provided does not include data regarding the phase change (e.g., the enthalpy of vaporization), which is necessary to calculate entropy change during a phase transition. The entropy provided (17.2 kJ/(mol*K)) is the molar entropy at a certain temperature, not the change in entropy due to vaporization.

The entropy change when 1.55 moles of CCl₂F₂ vaporize at 25°C can be calculated using the formula:

ΔS = n * S entropy = 1.55 mol * 17.2 kJ/(mol*K) = 26.6 kJ/K

This means that the entropy change is 26.6 kJ/K.

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