High School

A round copper wire of length 0.92 km and diameter 1.03 mm is found to have a resistance of 22 Ω. If there is one electron for each atom of Cu and if the voltage drop along the wire is 35.9 V, what is the electron drift velocity?

Given:
- Density of Cu = 8.9 tonnes/m\(^3\)
- Relative atomic mass = 63.54 g/mole

Answer :

Final answer:

The electron drift velocity is calculated using the length, diameter and resistivity of the copper wire, the voltage drop, and the atomic properties of copper. Information about the number of free electrons available for conduction in the wire is derived from the atomic mass and density of copper. The drift velocity tells us how quickly electrons move through the wire.

Explanation:

The electron drift velocity is a measure of how quick the flow of electrons is along a conductor. To calculate it, we first need to determine the number of free electrons in the given copper wire using the given density of Copper (d = 8.9 g/cm³), length of the wire (L = 0.92 km), diameter of the wire (d = 1.03 mm) and the relative atomic mass of Copper (Ar = 63.54 g/mole). From the number of free electrons (N), the cross-sectional area of the wire (A), the current in the wire (I) (calculated from the given voltage drop and resistance using Ohm's law) and the charge of an electron (e = 1.6 x 10^-19 C), we calculate the electron drift velocity (v) using the formula: v = I / (NeA)

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