High School

In the laboratory, a student finds that it takes 38.6 Joules to increase the temperature of 10.5 grams of solid tin from 21.0 to 39.4 degrees Celsius.

The specific heat of tin calculated from her data is ____________ J/g°C.

Answer :

The specific heat of tin calculated from the given data is approximately 0.206 J/g°C.

To calculate the specific heat of tin, we can use the formula Q = mcΔT, where Q is the energy change, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, the energy change (Q) is given as 38.6 Joules, the mass (m) is 10.5 grams, and the temperature change (ΔT) is 39.4 °C - 21.0 °C = 18.4 °C.

Plugging these values into the formula, we get:

38.6 J = (10.5 g) * c * (18.4 °C)

To solve for c, we divide both sides of the equation by (10.5 g * 18.4 °C):

c = 38.6 J / (10.5 g * 18.4 °C)

Evaluating the expression, we find that the specific heat of tin calculated from the given data is approximately 0.206 J/g°C.

Learn more about specific heat here;

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