High School

How much heat transfer (in kilocalories) is required to thaw a 0.450-kg package of frozen vegetables originally at 0°C if their heat of fusion is the same as that of water?

Latent heat or heat of fusion for vegetables = 79.8 kcal/kg.

A. 35.9 kcal
B. 40.2 kcal
C. 79.8 kcal
D. 90.0 kcal

Answer :

Final answer:

To thaw a 0.450-kg package of frozen vegetables at 0°C with the heat of fusion of water, a. 35.9 kilocalories of heat transfer is required.

Explanation:

To calculate the heat transfer required to thaw a 0.450-kg package of frozen vegetables at 0°C with a latent heat of fusion equivalent to that of water (79.8 kcal/kg), we use the formula:

Heat transfer (Q) = mass (m) × latent heat of fusion (L_f)

Here,

  • Mass (m) = 0.450 kg
  • Latent heat of fusion (L_f) = 79.8 kcal/kg

Therefore, the heat transfer required:

Q = 0.450 kg × 79.8 kcal/kg

Q = 35.91 kcal

After rounding to two decimal places, the heat transfer required is 35.9 kcal.

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