From Questions to Solutions

Find [tex] f(1) [/tex] given [tex] f(x) = 3x - 4 [/tex], [tex] g(x) = 46 - 17x [/tex], [tex] h(x) = 53 [/tex]. A. 29 B. 1 C. [tex]

What is the output of the following pseudocode? ``` set f to 1 set g to 0 repeat until f > 16 change g by f change f by 7

The specific heat of liquid ethanol, \(\text{C}_2\text{H}_5\text{OH}(l)\), is 2.46 J/g·°C, and the heat of vaporization is 39.3 kJ/mol. The boiling point of ethanol is 78.3 °C. What amount of enthalpy

Given an actual demand of 100, a forecasted value of 94, and an alpha of .4, the simple exponential smoothing forecast for the next period would be: O 100.2 O

How many kJ of heat energy would be absorbed when 175.0 g of ethanol, \(\text{C}_2\text{H}_5\text{OH}\), vaporizes at its boiling point, given the enthalpy of vaporization of ethanol is 39.3 kJ/mol?

What is 39.3 °C in °F?

Write an equation and solve. Round to the nearest hundredth where necessary. 58 is 100% of what number? A.) 1 = 58 • x; 39.4 B.) 58 = 1 •

A map of a new dog park shows that it is triangular, with sides measuring 18.5 m, 36.9 m, and 16.9 m. Are these dimensions correct? Explain your reasoning.

Gas Laws Fact Sheet \[ \begin{array}{|l|l|} \hline \text{Ideal gas law} & PV = nRT \\ \hline \text{Ideal gas constant} & \begin{array}{l} R = 8.314 \text{ (J/mol·K)} \\ \text{or} \\ R

Find the area of a triangle with sides measuring 15 m, 25 m, and 20 m. A. 38.2 m² B. 150 m² C. 42.4 m² D. 106.1 m²

The temperature of a 12.58 g sample of calcium carbonate [CaCO3 (s)] increases from 23.6 °C to 38.2 °C. If the specific heat of calcium carbonate is 0.82 J/g-K, how

Given \(\triangle PQR\) and \(\triangle STU\), what is \(m \angle T\)? A. 14 B. 70° C. 28 D. P E. 46 F. 21 G. R

In weather and climate, which temperature scales are used? 1) Celsius and Fahrenheit 2) Kelvin and Fahrenheit 3) Celsius and Kelvin

How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph

Barbara is converting [tex]$78^{\circ} F$[/tex] to degrees Celsius. First, she subtracts 32 from 78. What is the next step? A. Multiply 46 by [tex]$\frac{5}{9}$[/tex] B. Multiply 46 by [tex]$\frac{9}{5}$[/tex] C.